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Infosys Aptitude Questions and Answers with Explanation PDF Download: In this article, we have provided Infosys Aptitude Questions and Answers with Explanation. From this page, candidates can gather the sample Infosys Aptitude Questions and Answers. By practicing these questions, job aspirants can assess the difficulty level of the test as well, and he/she can save time while attempting the online exam. By learning these Infosys Aptitude Questions and Answers, students can manage time easily during the actual exam.
Infosys Aptitude Questions and Answers with Explanation
Number of Questions: 10
Time Limit: 25 mins.
By analyzing, we have also designed the approximate number of questions that may be asked from each topic of the Aptitude section in the table below. Kindly take a look at it.
| Topics Questions | s asked ( Approximately) |
|---|---|
| Averages | 2-4 Questions |
| Profits & Loss | 3-4 Questions |
| Percentages | 2-4 Questions |
| Ratio and Proportion | 1-3 Questions |
| Boats and Streams | 1-2 Questions |
| Simple Interest | 2-3 Questions |
| Compound Interest | 2-4 Questions |
| Volumes | 2-3 Questions |
| Probability | 1-3 Questions |
| Partnership | 1-3 Questions |
| Problems on Boats and Streams | 1-3 Questions |
Download Infosys Aptitude Questions and Answers in PDF format.
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Sample Infosys Aptitude Questions and Answers with Explanation
1. The average age of 30 boys in a class is equal to 14 years. When the age of the class teacher is included, the average becomes 15 years. Find the age of the class teacher?
A. 45
B. 42
C. 50
D. 44
Answer – A. 45
Explanation:
Given that
Total ages of 30 boys = 14 x 30 = 420 years
Total age when class teacher is included = 15 x 31 = 465 years
Age of class teacher = 465 – 420 = 45 years
Hence, the age of the class teacher is 45 years.
2. The average of 11 numbers is 10.9. If the average of the first six is 10.5 and that of the last six is 11.4, the sixth number is?
A. 11.4
B. 11.5
C. 11.0
D. 11.3
Answer – B. 11.5
Explanation:
Given, 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
Therefore, 6th number = 11.5
3. A shop dealer makes his goods 25% above CP and then, while selling, gives a discount of 12% on MP. Find his profit %?
A. 15%
B. 12%
C. 11%
D. 10%
Answer – D. 10%
Explanation:
Let Cost Price (CP) = 100
Market Price (MP) = 125
Profit = 125*88/100 = 110
110 – 100 = 10%.
4. A and B rent a pasture for 10 months. I put in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?
A. 120
B. 280
C. 180
D. 200
Answer – B. 280
Explanation:
According to the given data
80* 7: x* 3 = 1:1 1/2
560: 3x = 2: 3
x = 280
5. Rama Krishna can finish a work in 20 days, and Suresh in 25 days. They both work together for 5 days, and then Suresh goes away. In how many days will Rama Krishna complete the remaining work?
A. 10 days
B. 11 days
C. 8 days
D. 9 days
Answer – B. 11 days
Explanation:
Let’s assume the completion of the remaining work by Ramesh is x, then, according to the given information
(5 + x)/20 + 5/25 = 1 => x = 11 days
6. If P can do a work in 6 days and Q can do the same work in 8 days. If R, who can do the same work in 12 days, joins them, then the work will be completed in how many days?
A. 7/3 days
B. 8/3 days
C. 10/3 days
D. 11/3 days
Answer – B. 8/3 days
Explanation:
1/6 + 1/8 + 1/12 = 1/d.
D = 8/3 days
Therefore, the work will be completed in 8/3 days.
7. 5 men and 10 boys can do a piece of work in 30 days, and 8 men and 12 boys can do the work in 20 days. Then, the ratio of the daily work done by a man to that of the boy.
A. 6:1
B. 7:3
C. 4:5
D. 5:1
Answer – A. 6:1
Explanation:
5m + 10b = 1/30 and 8m + 12b = 1/20
after solving we get m = 1/200 and b = 1/1200
so required ratio = (1/200) : (1/1200) = 6:1
Hence, the ratio of daily work done by a man to that boy is 6:1.
8. A man spends 60% of his income. His income has increased by 20% and his expenditure has also increased by 10%. Find the percentage decrease in his savings?
A. 15%
B. 20%
C. 25%
D. 10%
Answer – D. 10%
Explanation:
Let us assume initially that income is 100.
So, expenditure = 60 and saving = 40
Now the income has increased by 20% that is 120.
So, expenditure = (70/100)*120 = 84 and saving = 36
so % percent decrease in saving = (4/40)*100 = 10%
9. Rani mixes 70kg of sugar worth Rs 28.50 per kg with 100kg of sugar worth Rs 30.50 per kg. At what rate shall he sell the mixture to gain 10 %?
A. Rs.29.75
B. Rs.32.64
C. Rs.31.50
D. Rs.30.46
Answer – B. Rs . 32.64
Explanation:
70/100 = 100x – 30.50(110)/28.50(110)-100x
0.7 = 100x-3355/3135-100x
2194.5 – 70x = 100x-3355
170x = 5549.5
X = 32.64
10. How much water must be added to a bucket that contains 40 liters of milk at the cost price of Rs . 3.50 per liter so that the cost of milk reduces to Rs. 2 per liter?
A. 25 liters
B. 28 litres
C. 30 liters
D. 35 liters
Answer – C. 30 liters
Explanation:
Total cost price =Rs(40 x 7/2) = Rs.140
Cost per litre =Rs.2
Total quantity = 140/2 = 70 liters.
Water to be added =(70-40) =30 liters.
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